update post, josh-oap-1-2
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@@ -394,12 +394,16 @@ $$\begin{equation}
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  定义一个复数权矢量为
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<a id="ComplexWeightVector"></a>
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$$\begin{equation} \label{ComplexWeightVector}
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\vec{w}^\mathrm{H} = [w_0^\ast, w_1^\ast, \cdots, w_{N-1}^\ast]
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\end{equation}$$
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则式 $\eqref{ArrayResponseToUnitPlaneWaveInTimeDomain}$ 成为
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<a id="FrequencyWavenumberResponseWithComplexWeigh"></a>
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$$\begin{equation}
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y\left( t,\vec{k} \right) = \vec{w}^\mathrm{H} \vec{v}_{\vec{k}}\left( \vec{k} \right) e^{j\omega t}
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\end{equation}$$
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@@ -35,14 +35,14 @@ $$\begin{equation} \label{ElementLocation}
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\begin{cases}
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p_{x_n} = 0 \\
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p_{y_n} = 0 \\
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p_{z_n} = \left( n - \displaystyle\frac{N-1}{2} \right) d
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p_{z_n} = \left( n - \frac{N-1}{2} \right) d
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\end{cases}
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, \, n = 0,1,\cdots,N-1
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\end{equation}$$
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为了确定阵列流形矢量 $\vec{v}_{\vec{k}}\left(\vec{k}\right)$, 把式 $\eqref{ElementLocation}$ 代入到[阵列流形矢量的定义][], 得到
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为了确定阵列流形矢量 $\vec{v}_{\vec{k}}\left(\vec{k}\right)$,把式 $\eqref{ElementLocation}$ 代入到[阵列流形矢量的定义][],得到
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$$\begin{equation}
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$$\begin{equation} \label{ManifoldVectorOfULA}
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\vec{v}_{\vec{k}}\left(k_z\right) = \left[\begin{array}{c}
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e^{j \left( \frac{N-1}{2} \right) k_z d} \\
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e^{j \left( \frac{N-1}{2} - 1\right) k_z d} \\
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@@ -63,4 +63,33 @@ $$\begin{equation}
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k_0 \triangleq \left| \vec{k} \right| = \frac{2\pi}{\lambda}
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\end{equation}$$
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意线阵在 0 方向是没有分辨能力的。将[复权矢量][] 和式 $\eqref{ManifoldVectorOfULA}$ 代入[用复权矢量表示的波数-频率响应函数][],得到 ULA 在角度域的频率-波数响应函数
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$$\begin{equation} \label{WFRFOfULAInAngleDomain}
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\begin{aligned}
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\vec{\varUpsilon}(\omega,k_z) &= \vec{w}^\mathrm{H}\vec{v}_{\vec{k}}\left(k_z\right) \\
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&= \sum_{n=0}^{N-1} w_n^\ast e^{-j\left( n - \frac{N-1}{2} k_z d \right)}
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\end{aligned}
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\end{equation}$$
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定义下面的变量也是很有用的(波数在 $z$ 轴上的投影,乘以阵元间距,也即扫过一个阵元间距时,波数的变化量在 $z$ 轴上的体现):
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$$\begin{equation} \eqref{DefinitionOfWavenumberDiffOfTwoElements}
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\psi = -k_z d = \frac{2\pi}{\lambda}\cos\theta\cdot d = \frac{2\pi}{\lambda}u_z d
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\end{equation}$$
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其中 $u_z$ 是针对 $z$ 轴的方向余弦,
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$$\begin{equation}
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u_z = \cos\theta
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\end{equation}$$
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将式 $\eqref{DefinitionOfWavenumberDiffOfTwoElements}$ 代入式 $\eqref{WFRFOfULAInAngleDomain}$,得到
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$$\begin{equation}
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\vec{\varUpsilon}_\psi(\psi) = e^{-j \frac{N-1}{2} \psi } \sum_{n=0}^{N-1} w_n^\ast e^{j n\psi}
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\end{equation}$$
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[阵列流形矢量的定义]: https://josh-gao.top/posts/8b61f5a7.html#DefinitionOfArrayManifoldVector
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[复权矢量]: https://josh-gao.top/posts/8b61f5a7.html#ComplexWeightVector
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[用复权矢量表示的波数-频率响应函数]: https://josh-gao.top/posts/8b61f5a7.html#FrequencyWavenumberResponseWithComplexWeigh
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