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title: Josh 的学习笔记之数字信号处理(Part 2——离散傅里叶级数 DFS)
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comments: true
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copyright: true
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toc:
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max_depth: 4
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tags:
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- 数字信号和处理
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- DSP
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- 离散傅里叶级数
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- DFS
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- 连续时间傅里叶变换
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- 连续傅里叶级数
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- 离散时间傅里叶变换
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- DTFT
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- 圆周卷积
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- 周期卷积
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- 共轭对称
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categories:
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- - Josh 的学习笔记
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- 数字信号处理
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abbrlink: 3345523e
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date: 2023-04-14 18:43:17
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---
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# 1. 傅里叶变换的几种形式
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## 1.1 非周期连续时间信号的傅里叶变换
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  非周期连续时间信号的傅里叶变换(连续时间傅里叶变换,Continuous-Time Fourier Transform, CTFT)的形式为:
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$$\begin{equation}
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X_a\left(j\Omega\right)=\int_{-\infty}^{\infty}{x_a\left(t\right)e^{-j\Omega t}\mathrm{d}t}
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\end{equation}$$
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$$\begin{equation}
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x_a\left(t\right)=\frac{1}{2\pi}\int_{-\infty}^{\infty}{X_a\left(j\Omega\right)e^{j\Omega t}\mathrm{d}\Omega}
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\end{equation}$$
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<!-- more -->
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## 1.2 周期连续时间信号的傅里叶变换
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  周期连续时间信号的傅里叶变换(连续傅里叶级数,Continous Fourier Series, CFS)的形式为:
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$$\begin{equation}
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X\left(m\Omega\right)=\frac{1}{t_p}\int_{-\frac{t_p}{2}}^{\frac{t_p}{2}}{x_a\left(t\right)e^{-jm\Omega t}\mathrm{d}t}
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\end{equation}$$
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$$\begin{equation}
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x_a\left(t\right)=\sum_{m=-\infty}^{\infty}{X\left(m\Omega\right)e^{jm\Omega t}}
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\end{equation}$$
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其中 $t_p$ 为信号的周期,频域相邻谱线间角频率增量 $\Omega=\dfrac{2\pi}{t_p}$。
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## 1.3 非周期离散时间信号的傅里叶变换
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  非周期离散时间信号的傅里叶变换(离散时间傅里叶变换,Discrete-Time Fourier Transform, DTFT)的形式为:
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$$\begin{equation}
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X\left(e^{j\omega}\right)=\sum_{n=-\infty}^{\infty}{x\left(n\right)e^{-j\omega n}}
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\end{equation}$$
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$$\begin{equation}
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x\left(n\right)=\frac{1}{2\pi}\int_{-\pi}^{\pi}{X\left(e^{j\omega}\right)e^{j\omega n}\mathrm{d}\omega}
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\end{equation}$$
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取样频率 $f_s=\dfrac{1}{T}$,取样角频率 $\Omega_s=\dfrac{2\pi}{T}$,取样数字频率$\omega_s=2\pi$。
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## 1.4 周期离散时间信号的傅里叶变换
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  周期离散时间信号的傅里叶变换(离散傅里叶级数,Discrete Fourier Series, DFS)的形式为:
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$$\begin{equation}
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\widetilde{X}\left(k\right)=\left.\widetilde{X}\left(e^{j\omega}\right)\right|_{\omega=k\frac{2\pi}{N}}=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j\frac{2\pi}{N}kn}}=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)W_N^{kn}}
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\end{equation}$$
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$$\begin{equation}
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\widetilde{x}\left(n\right)=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}kn}}=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)W_N^{-kn}}
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\end{equation}$$
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其中 $N$ 为一个周期内的点数,时域相邻谱线间隔为 $T$ ,频域相邻谱线间隔为 $\dfrac{1}{NT}$,以数字频率表征时为 $\dfrac{2\pi}{N}$。
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> **由以上,在一个域中对函数进行取样,两取样点间增量的倒数,必是另一个域中的周期。**
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# 2. 离散傅里叶级数(DFS)的推导
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## 2.1 正变换
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  令 $x\left(n\right)$ 为 $N$ 点长的离散序列,则其 DTFT(上标“~”用来表征周期性)
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$$\begin{equation}
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\widetilde{X}\left(e^{j\omega}\right)=\sum_{n=-\infty}^{\infty}{x\left(n\right)e^{-j\omega n}}=\sum_{n=0}^{N-1}{x\left(n\right)e^{-j\omega n}}
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\end{equation}$$
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对 $\widetilde{X}\left(e^{j\omega}\right)$ 取样,使其称为周期离散频率函数,由此时域序列 $x\left(n\right)$ 周期化为 $\widetilde{x}\left(n\right)$,令其谱线间隔为 $T$,则时域序列的周期为 $NT$,所以对频谱取样的谱间距为 $\dfrac{1}{NT}$,以数字频率表征时,谱间距
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$$\begin{equation}
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\omega_\mathrm{I}=\frac{2\pi}{N}
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\end{equation}$$
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因此,以数字频率 $\omega$ 为变量的 $X\left(e^{j\omega}\right)$ 被离散化时,其变量 $\omega$ 变为
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$$\begin{equation}
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\omega=k\omega_\mathrm{I}=k\frac{2\pi}{N}
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\end{equation}$$
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因此离散周期序列 $\widetilde{x}\left(n\right)$ 的傅里叶级数可写为
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$$\begin{equation}
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\widetilde{X}\left(k\right)=\left.\widetilde{X}\left(e^{j\omega}\right)\right|_{\omega=k\frac{2\pi}{N}}=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j\frac{2\pi}{N}kn}}=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)W_N^{kn}}
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\end{equation}$$
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并将数字域频率用 $k$ 简化表示。且
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$$\begin{equation}
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\widetilde{X}\left(k+N\right)=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j\frac{2\pi}{N}\left(k+N\right)n}}=\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j2\pi n}e^{-j\frac{2\pi}{N}kn}=}\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j\frac{2\pi}{N}kn}=}\widetilde{X}\left(k\right)
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\end{equation}$$
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即 $\widetilde{X}\left(k\right)$ 是以 $N$ 为周期的周期函数。
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## 2.2 逆变换
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  将正变换两边乘以 $e^{j\frac{2\pi}{N}kr}$,并在一个周期内求和,有
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$$\begin{equation}
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\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}kr}}=\sum_{k=0}^{N-1}{\left(\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)e^{-j\frac{2\pi}{N}kn}}\right)e^{j\frac{2\pi}{N}kr}}=N\left[\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)\left(\frac{1}{N}\sum_{k=0}^{N-1}e^{j\frac{2\pi}{N}k\left(r-n\right)}\right)}\right]
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\end{equation}$$
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由正交定理
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$$\begin{equation}
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\frac{1}{N}\sum_{k=0}^{N-1}e^{j\frac{2\pi}{N}k\left(r-n\right)}=
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\begin{aligned}
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\begin{cases}
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1,&r=n\\
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0,&r≠n
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\end{cases}
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\end{aligned}
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\end{equation}$$
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则
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$$\begin{equation}
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\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}kr}}=N\left.\left[\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)}\right]\right|_{n=r}=N\widetilde{x}\left(r\right)
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\end{equation}$$
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可得逆离散傅里叶变换
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$$\begin{equation}
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\widetilde{x}\left(n\right)=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}kn}}=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)W_N^{-kn}}
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\end{equation}$$
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且
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$$\begin{equation}
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\widetilde{x}\left(n+mN\right)=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}k\left(n+mN\right)}}=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)e^{j\frac{2\pi}{N}kn}e^{j2\pi km}}=\widetilde{x}\left(n\right)
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\end{equation}$$
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即 $\widetilde{x}\left(n\right)$ 是以 $N$ 为周期的周期函数。
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# 3. 离散傅里叶级数(DFS)的性质
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## 3.1 线性性质
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$$\begin{equation}
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\mathrm{DFS}\left[a{\widetilde{x}}_1\left(n\right)+{b\widetilde{x}}_2\left(n\right)\right]=a{\widetilde{X}}_1\left(k\right)+b{\widetilde{X}}_2\left(k\right)
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\end{equation}$$
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## 3.2 时移性质
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$$\begin{equation}
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\mathrm{DFS}\left[\widetilde{x}\left(n+m\right)\right]=W_N^{-mk}\widetilde{X}\left(k\right)
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\end{equation}$$
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证明:
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$$\begin{equation}
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\begin{aligned}
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\mathrm{DFS}\left[\widetilde{x}\left(n+m\right)\right]&=\sum_{n=0}^{N-1}{\widetilde{x}\left(n+m\right)W_N^{nk}}=\sum_{n=m}^{N-1+m}{\widetilde{x}\left(n\right)W_N^{\left(n-m\right)k}}=\sum_{n=m}^{N-1+m}{\widetilde{x}\left(n\right)W_N^{nk}W_N^{-mk}}
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\\
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&\xlongequal{利用\widetilde{x}\left(n\right)和W_N^{nk}的周期性}\left(\sum_{n=0}^{N-1}{\widetilde{x}\left(n\right)W_N^{nk}}\right)W_N^{-mk}=W_N^{-mk}\widetilde{X}\left(k\right)
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\end{aligned}
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\end{equation}$$
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## 3.3 频移性质
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$$\begin{equation}
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\mathrm{IDFS}\left[\widetilde{X}\left(k+l\right)\right]=W_N^{nl}\widetilde{x}\left(n\right)
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\end{equation}$$
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证明:
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$$\begin{equation}
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\begin{aligned}
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\mathrm{IDFS}\left[\widetilde{X}\left(k+l\right)\right]&=\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}\left(k+l\right)W_N^{-kn}}=\frac{1}{N}\sum_{k=l}^{N-1+l}{\widetilde{X}\left(k\right)W_N^{-\left(k-l\right)n}}=\frac{1}{N}\sum_{k=l}^{N-1+l}{\widetilde{X}\left(k\right)W_N^{-kn}W_N^{nl}}
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\\
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&\xlongequal{利用\widetilde{X}\left(n\right)和W_N^{-nk}的周期性}\frac{1}{N}\left(\sum_{k=0}^{N-1}{\widetilde{X}\left(k\right)W_N^{-kn}}\right)W_N^{nl}=W_N^{nl}\widetilde{x}\left(n\right)
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\end{aligned}
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\end{equation}$$
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## 3.4 时域周期卷积
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$$\begin{equation}
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{\widetilde{x}}_1\left(n\right)\odot{\widetilde{x}}_2\left(n\right)=\mathrm{IDFS}\left[{\widetilde{X}}_1\left(k\right)\cdot{\widetilde{X}}_2\left(k\right)\right]
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\end{equation}$$
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证明:
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$$\begin{equation}
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\begin{aligned}
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\mathrm{IDFS}\left[{\widetilde{X}}_1\left(k\right)\cdot{\widetilde{X}}_2\left(k\right)\right]&=\frac{1}{N}\sum_{k=0}^{N-1}{\left[{\widetilde{X}}_1\left(k\right)\cdot{\widetilde{X}}_2\left(k\right)\right]W_N^{-nk}}\\
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&=\frac{1}{N}\sum_{k=0}^{N-1}{\left[\sum_{m=0}^{N-1}{\widetilde{x}}_1\left(m\right)W_N^{mk}\right]{\widetilde{X}}_2\left(k\right)W_N^{-nk}}\\
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&=\frac{1}{N}\sum_{k=0}^{N-1}\left[\sum_{m=0}^{N-1}{\widetilde{x}}_1\left(m\right){\widetilde{X}_2\left(k\right)W}_N^{-\left(n-m\right)k}\right]\\
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&=\sum_{m=0}^{N-1}{\widetilde{x}}_1\left(m\right)\left[\frac{1}{N}\sum_{k=0}^{N-1}{\widetilde{X}_2\left(k\right)W}_N^{-\left(n-m\right)k}\right]\\
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&=\sum_{m=0}^{N-1}{\widetilde{x}}_1\left(m\right){\widetilde{x}}_2\left(n-m\right)
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\\
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&={\widetilde{x}}_1\left(n\right)\odot{\widetilde{x}}_2\left(n\right)
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\end{aligned}
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\end{equation}$$
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> 注:此处用 $\odot$ 表示圆周卷积,不同教材中圆周卷积的符号表述可能不同。
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## 3.5 频域周期卷积
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$$\begin{equation}
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\mathrm{DFS}\left[{\widetilde{x}}_1\left(n\right){\widetilde{x}}_2\left(n\right)\right]=\frac{1}{N}\left[{\widetilde{X}}_1\left(k\right)\odot{\widetilde{X}}_2\left(k\right)\right]
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\end{equation}$$
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证明:
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$$\begin{equation}
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\begin{aligned}
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\mathrm{DFS}\left[{\widetilde{x}}_1\left(n\right){\widetilde{x}}_2\left(n\right)\right]&=\sum_{n=0}^{N-1}{\widetilde{X}_1\left(n\right){\widetilde{x}}_2\left(n\right)W_N^{kn}}=\sum_{n=0}^{N-1}\left[\frac{1}{N}\sum_{r=0}^{N-1}{\widetilde{X}_1\left(r\right)W_N^{-rn}}\right]{\widetilde{x}}_2\left(n\right)W_N^{kn}\\
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&=\frac{1}{N}\sum_{n=0}^{N-1}\left[\sum_{r=0}^{N-1}{\widetilde{X}_1\left(r\right){\widetilde{x}}_2\left(n\right)W_N^{\left(k-r\right)n}}\right]\\
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&=\frac{1}{N}\sum_{r=0}^{N-1}{\widetilde{X}}_1\left(r\right)\left[\sum_{k=0}^{N-1}{\widetilde{X}_2\left(n\right)W_N^{\left(k-r\right)n}}\right]\\
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&=\frac{1}{N}\sum_{r=0}^{N-1}{\widetilde{X}}_1\left(r\right){\widetilde{X}}_2\left(k-r\right)\\
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&=\frac{1}{N}\left[{\widetilde{X}}_1\left(k\right)\odot{\widetilde{X}}_2\left(k\right)\right]
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\end{aligned}
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\end{equation}$$
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> 注:此处用 $\odot$ 表示圆周卷积,不同教材中圆周卷积的符号表述可能不同。
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